LINQ練習題 - 兩個集合做Union並且做Group彙總

LINQ練習題 - 兩個集合做Union並且做Group彙總

先定義一下型別

public class SomeStatistics
{
    public DateTime Day { get; set; }
    public int Correct { get; set; }
    public int Incorrect { get; set; }
}

 

然後有兩個此型別的集合

List<SomeStatistics> list1 = new List<SomeStatistics>();
list1.Add(new SomeStatistics() { Day = new DateTime(2010, 8, 1), Correct = 10, Incorrect = 2 });
list1.Add(new SomeStatistics() { Day = new DateTime(2010, 8, 2), Correct = 5, Incorrect = 3 });
list1.Add(new SomeStatistics() { Day = new DateTime(2010, 8, 3), Correct = 2, Incorrect = 4 });
list1.Add(new SomeStatistics() { Day = new DateTime(2010, 8, 4), Correct = 1, Incorrect = 5 });
 
List<SomeStatistics> list2 = new List<SomeStatistics>();
list2.Add(new SomeStatistics() { Day = new DateTime(2010, 7, 28), Correct = 10, Incorrect = 2 });
list2.Add(new SomeStatistics() { Day = new DateTime(2010, 7, 29), Correct = 11, Incorrect = 3 });
list2.Add(new SomeStatistics() { Day = new DateTime(2010, 7, 30), Correct = 12, Incorrect = 4 });
list2.Add(new SomeStatistics() { Day = new DateTime(2010, 7, 31), Correct = 13, Incorrect = 5 });
list2.Add(new SomeStatistics() { Day = new DateTime(2010, 8, 4), Correct = 5, Incorrect = 10 });

兩個集合的Union是這樣

image

可以看到最後有兩筆資料的Day是相同的,需求是要將Day做Group然後Correct、Incorrect的兩項欄位要做彙總

 

作法一

List<SomeStatistics> list3 = new List<SomeStatistics>();
list3.AddRange(list1);
 
foreach (var item in list2)
{
    if (!list3.Select(s=>s.Day).Contains(item.Day))
    {
        list3.Add(item);
    }
    else
    {
        var target = list3.Where(s => s.Day == item.Day).FirstOrDefault();
        target.Correct += item.Correct;
        target.Incorrect += item.Incorrect;
    }
}

結果顯示

image

 

作法二

List<SomeStatistics> result = new List<SomeStatistics>();
 
foreach (var item in list1.Union(list2).GroupBy(s=>s.Day))
{
    result.Add(new SomeStatistics() { 
        Day = item.Key,
        Correct = list1.Union(list2).Where(s => s.Day == item.Key).Select(s => s.Correct).Sum(),
        Incorrect = list1.Union(list2).Where(s => s.Day == item.Key).Select(s => s.Incorrect).Sum()
    });
}

 

結果顯示

image

 

 

第一個方法是比較制式的,而第二個作法就有用到GroupBy與Sum方法

只是個練習題,但我想應該還有更加精簡而有效率的方法吧!?

希望能有朋友可以不吝指教更好的方法

謝謝

純粹是在寫興趣的,用寫程式、寫文章來抒解工作壓力